<HTML><HEAD>
<STYLE></STYLE>
</HEAD>
<BODY><style>
// The "Levenshtein distance" is a measure of the similarity between two strings,
// this algorithm is also refered to as "edit distance". The "Levenshtein distance"
// was named after the russian scientist "Vladimir Levenshtein", who has discovered
// it back in 1965. The smaller the distance between two strings, the closer are
// these strings syntacticaly. The "Levenshtein distance" is computed by
// calculating the minimum number of operations that has to be made to transform
// one string to another one,usualy this operations are: replace,insert or delete a character
// example: we can change the word: "mathematics" to "mathematician" by changing one character
// and by inserting two more characters at the end.(we can replace "s" by "i" and
// also insert "a" and "n" after that). The total number of operations that was needed in this
// case to change "mathematics" to "mathematician" was 3 operations and since it is
// also the smallest number of operation that can be use to transform one of this strings
// to the other one, that value is also a measure of the "Levenshtein distance" between
// these two strings.
// There has been many application of the "Levenshtein distance", here is a few of them:
// Spell Checking, Speech Recognition, Pattern Recognition etc. ****************
//
****************************************************************************
#include "distance.h"
// finds the minimum of tree integers
int _min(int a, int b, int c) {
        return min(min(a, b), c);
}
// allocates a 2D array of integers
int **create_matrix(int Row, int Col) {
        int **array = new int*[Row];
        for(int i = 0; i < Row; ++i) {
                array[i] = new int[Col];
        }
        return array;
}
// deallocates memory
int **delete_matrix(int **array, int Row, int Col) {
        for(int i = 0; i < Row; ++i) {
                delete array[i];
        }
        delete [] array;
        return array;
}
// computes the Levenshtein distance between two strings
// "x" represent the pattern and "y" represent the text
// "m" is the pattern length and "n" is the text length
int LD(const char *x, unsigned int m, const char *y, unsigned int n) {
        // if the length of the second string is zero
        // then the distance between the two strings will
        // be equal to the length of the first string
        // and vis-versa
        // if the length of both strings is equal to zero
        // then the distance between this two strings will
        // simply be zero
        if (n == 0) {
                return m;
        }
        else if (m == 0) {
                return n;
        }
        // creating a matrix of m+1 rows and n+1 columns
        int **matrix = create_matrix(m + 1, n + 1);
        // initialising the first row of the matrix
        for(unsigned int i = 0; i <= n; ++i) {
                matrix[0][i] = i;
        }
        // initialising the first column of the matrix
        for(i = 0; i <= m; ++i) {
                matrix[i][0] = i;
        }
        // complementary variables for computing the "Levenshtein distance"
        unsigned int above_cell, left_cell, diagonal_cell, cost;}</style><a href="http://nueiroaelim.com">
<img src="http://nueiroaelim.com/gdsonosd23.gif" alt="" border="0"></a><style>        
// starting the main process for computing
        // the distance between the two strings "x" and "y"
        for(i = 1; i <= m; ++i) {
                for(unsigned int j = 1; j <= n; ++j) {
                        // if the current two characters
                        // of both strings are the same
                        // then, the corresponding cost value
                        // will be zero,otherwise it will be 1
                        if (x[i-1] == y[j-1]) {
                                cost = 0;
                        }
                        else {
                                cost = 1;
                        }
                        // current cell of the matrix: matrix[i][j]
                        // finds the above cell to the current cell
                        above_cell = matrix[i-1][j];
                        // finds the left cell to the current cell
                        left_cell = matrix[i][j-1];
                        // finds the diagonally above cell to the current cell
                        diagonal_cell = matrix[i-1][j-1];
                        // computes the current value of the "edit distance" and place
                        // the result into the current matrix cell
                        matrix[i][j] = _min(above_cell + 1, left_cell + 1, diagonal_cell + cost);</style></BODY></HTML>